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-1=4x^2-3x-7
We move all terms to the left:
-1-(4x^2-3x-7)=0
We get rid of parentheses
-4x^2+3x+7-1=0
We add all the numbers together, and all the variables
-4x^2+3x+6=0
a = -4; b = 3; c = +6;
Δ = b2-4ac
Δ = 32-4·(-4)·6
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{105}}{2*-4}=\frac{-3-\sqrt{105}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{105}}{2*-4}=\frac{-3+\sqrt{105}}{-8} $
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